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reformat code to fit guidelines
remember which translation paths are multi-step paths git-svn-id: https://origsvn.digium.com/svn/asterisk/branches/1.2@11062 65c4cc65-6c06-0410-ace0-fbb531ad65f3
This commit is contained in:
75
translate.c
75
translate.c
@@ -55,7 +55,8 @@ static struct ast_translator *list = NULL;
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struct ast_translator_dir {
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struct ast_translator *step; /*!< Next step translator */
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int cost; /*!< Complete cost to destination */
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unsigned int cost; /*!< Complete cost to destination */
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unsigned int multistep; /*!< Multiple conversions required for this translation */
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};
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struct ast_frame_delivery {
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@@ -271,57 +272,63 @@ static void rebuild_matrix(int samples)
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{
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struct ast_translator *t;
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int changed;
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int x,y,z;
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int x, y, z;
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if (option_debug)
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ast_log(LOG_DEBUG, "Resetting translation matrix\n");
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bzero(tr_matrix, sizeof(tr_matrix));
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t = list;
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while(t) {
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if(samples)
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for (t = list; t; t = t->next) {
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if (samples)
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calc_cost(t, samples);
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if (!tr_matrix[t->srcfmt][t->dstfmt].step ||
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tr_matrix[t->srcfmt][t->dstfmt].cost > t->cost) {
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tr_matrix[t->srcfmt][t->dstfmt].cost > t->cost) {
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tr_matrix[t->srcfmt][t->dstfmt].step = t;
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tr_matrix[t->srcfmt][t->dstfmt].cost = t->cost;
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}
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t = t->next;
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}
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do {
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changed = 0;
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/* Don't you just love O(N^3) operations? */
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for (x=0; x< MAX_FORMAT; x++) /* For each source format */
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for (y=0; y < MAX_FORMAT; y++) /* And each destination format */
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if (x != y) /* Except ourselves, of course */
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for (z=0; z < MAX_FORMAT; z++) /* And each format it might convert to */
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if ((x!=z) && (y!=z)) /* Don't ever convert back to us */
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if (tr_matrix[x][y].step && /* We can convert from x to y */
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tr_matrix[y][z].step && /* And from y to z and... */
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(!tr_matrix[x][z].step || /* Either there isn't an x->z conversion */
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(tr_matrix[x][y].cost +
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tr_matrix[y][z].cost < /* Or we're cheaper than the existing */
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tr_matrix[x][z].cost) /* solution */
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)) {
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/* We can get from x to z via y with a cost that
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is the sum of the transition from x to y and
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from y to z */
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tr_matrix[x][z].step = tr_matrix[x][y].step;
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tr_matrix[x][z].cost = tr_matrix[x][y].cost +
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tr_matrix[y][z].cost;
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if (option_debug)
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ast_log(LOG_DEBUG, "Discovered %d cost path from %s to %s, via %d\n", tr_matrix[x][z].cost, ast_getformatname(x), ast_getformatname(z), y);
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changed++;
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}
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for (x = 0; x< MAX_FORMAT; x++) { /* For each source format */
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for (y = 0; y < MAX_FORMAT; y++) { /* And each destination format */
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if (x == y) /* Except ourselves, of course */
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continue;
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for (z=0; z < MAX_FORMAT; z++) { /* And each format it might convert to */
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if ((x == z) || (y == z)) /* Don't ever convert back to us */
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continue;
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if (tr_matrix[x][y].step && /* We can convert from x to y */
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tr_matrix[y][z].step && /* And from y to z and... */
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(!tr_matrix[x][z].step || /* Either there isn't an x->z conversion */
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(tr_matrix[x][y].cost +
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tr_matrix[y][z].cost < /* Or we're cheaper than the existing */
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tr_matrix[x][z].cost) /* solution */
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)) {
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/* We can get from x to z via y with a cost that
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is the sum of the transition from x to y and
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from y to z */
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tr_matrix[x][z].step = tr_matrix[x][y].step;
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tr_matrix[x][z].cost = tr_matrix[x][y].cost +
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tr_matrix[y][z].cost;
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tr_matrix[x][z].multistep = 1;
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if (option_debug)
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ast_log(LOG_DEBUG, "Discovered %d cost path from %s to %s, via %d\n", tr_matrix[x][z].cost, ast_getformatname(x), ast_getformatname(z), y);
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changed++;
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}
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}
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}
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}
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} while (changed);
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}
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/*! \brief CLI "show translation" command handler */
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static int show_translation(int fd, int argc, char *argv[])
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{
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