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Run predial routine on local;2 channel where you would expect.

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Before this patch, the predial routine executes on the ;1 channel of a
local channel pair.  Executing predial on the ;1 channel of a local
channel pair is of limited utility.  Any channel variables set by the
predial routine executing on the ;1 channel will not be available when the
local channel executes dialplan on the ;2 channel.

* Create ast_pre_call() and an associated pre_call() technology callback
to handle running the predial routine.  If a channel technology does not
provide the callback, the predial routine is simply run on the channel.

Review: https://reviewboard.asterisk.org/r/1903/


git-svn-id: https://origsvn.digium.com/svn/asterisk/trunk@366183 65c4cc65-6c06-0410-ace0-fbb531ad65f3
This commit is contained in:
Richard Mudgett
2012-05-10 21:29:41 +00:00
parent dd81b047db
commit 4ea636c776
4 changed files with 80 additions and 1 deletions
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17
main/channel.c
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@@ -5671,6 +5671,23 @@ struct ast_channel *ast_request(const char *type, struct ast_format_cap *request
return NULL;
}
int ast_pre_call(struct ast_channel *chan, const char *sub_args)
{
int (*pre_call)(struct ast_channel *chan, const char *sub_args);
ast_channel_lock(chan);
pre_call = ast_channel_tech(chan)->pre_call;
if (pre_call) {
int res;
res = pre_call(chan, sub_args);
ast_channel_unlock(chan);
return res;
}
ast_channel_unlock(chan);
return ast_app_exec_sub(NULL, chan, sub_args);
}
int ast_call(struct ast_channel *chan, const char *addr, int timeout)
{
/* Place an outgoing call, but don't wait any longer than timeout ms before returning.