Fix a callerid parsing issue. If someone formatted callerid like the

following: "name <number>" (including the quotation marks), then the parts
would be parsed as 

name: "name
number: number

This is because the closing quotation mark was not discovered since the number
and everything after was parsed out of the string earlier. Now, there is a check
to see if the closing quote occurs after the number, so that we can know if we
should strip off the opening quote on the name.

Closes AST-158



git-svn-id: https://origsvn.digium.com/svn/asterisk/branches/1.4@160943 65c4cc65-6c06-0410-ace0-fbb531ad65f3
This commit is contained in:
Mark Michelson
2008-12-04 16:44:18 +00:00
parent 16f94acd53
commit 5397638a2f

View File

@@ -964,7 +964,6 @@ int ast_is_shrinkable_phonenumber(const char *exten)
* input location name
* " foo bar " <123> 123 ' foo bar ' (with spaces around)
* " foo bar " NULL 'foo bar' (without spaces around)
* " foo bar <123>" 123 '" foo bar'
* The parsing of leading and trailing space/quotes should be more consistent.
*/
int ast_callerid_parse(char *instr, char **name, char **location)
@@ -978,6 +977,15 @@ int ast_callerid_parse(char *instr, char **name, char **location)
if ((ns = strchr(instr, '"')) && (ne = strchr(ns + 1, '"'))) {
*ns = *ne = '\0'; /* trim off the quotes */
*name = ns + 1; /* and this is the name */
} else if (ns) {
/* An opening quote was found but no closing quote was. The closing
* quote may actually be after the end of the bracketed number
*/
if (strchr(le + 1, '\"')) {
*ns = '\0';
*name = ns + 1;
ast_trim_blanks(*name);
}
} else { /* no quotes, trim off leading and trailing spaces */
*name = ast_skip_blanks(instr);
ast_trim_blanks(*name);